Math

z^2 -16z+39=0 Factor and solve

Asked by AnneS2 on 13 Oct 06:35

Last updated by anonymous on 14 Oct 10:53

1 Answers

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Answered by CherieS on 14 Oct 10:53

z^2 -16z+39=0

(z )(z ) ( -13)( -3)=0

(z-13) (z-3) = 0

Solve:

(z-13)=0

z-13+13=0+13

z=13

Solve:

(z-3) = 0

z-3+3 = 0+3

z=3