z^2 -15z+36=0 Factor and solve

Asked by AnneS2 12 years ago 10/8/2013 4:51 AM

Last updated by anonymous 12 years ago 10/9/2013 11:27 AM

Answered by CherieS 12 years ago 10/9/2013 11:27 AM

z^2 -15z+36=0

(z )(z ) ( -12)( -3)=0

(z-12) (z-3) = 0

Solve:

(z-12)=0

z-12+12=0+12

z=12

Solve:

(z-3) = 0

z-3+3 = 0+3

z=3