Math

y^2 -28y+160=0 Factor and solve

Asked by
Last updated by anonymous
1 Answers
Log in to answer

y^2 -28y+160=0

(y )(y ) ( -20)( -8)=0

(y-20) (y-8) = 0

Solve:

(y-20)=0

y-20+20=0+20

y=20

Solve:

(y-8) = 0

y-8+8 = 0+8

y=8