Math y^2 -28y+160=0 Factor and solve Asked by AnneS2 12 years ago 10/8/2013 4:46 AM Last updated by anonymous 12 years ago 10/9/2013 3:39 PM
y^2 -28y+160=0 (y )(y ) ( -20)( -8)=0 (y-20) (y-8) = 0 Solve: (y-20)=0 y-20+20=0+20 y=20 Solve: (y-8) = 0 y-8+8 = 0+8 y=8