Math (x^3 -x^2 +8x-8)/(x-1) Asked by AnneS2 on 08 May 03:22 Last updated by anonymous on 09 May 16:09
(x^3 -x^2 +8x-8)/(x-1) =x^2(x-1)=x^3-x^2 x^3 -x^2 +8x-8-x^3+x^2=+8x-8 =8(x-1)=8x-8 8x-8-8x+8=0 Answer:x^2+8 r 0
