Math (x^3 +13x^2 +39x-5)/(x+5) Asked by AnneS2 on 08 May 03:23 Last updated by anonymous on 09 May 16:05
(x^3 +13x^2 +39x-5)/(x+5) =x^2(x+5)=x^3+5 x^2 x^3 +13x^2 +39x-5-x^3-5x^2=8x^2+39x =8x(x+5)=8 x^2+40 x 8x^2+39x-8x^2-40x-5=-1x-5 =-1(x+5)=-x-5 -1x-5+x+5=0 answer: x^2+8x-1 r0