Math Solve for u+6y=32 and u+3y = 17 Asked by AnneS2 on 12 Jul 04:48 Last updated by anonymous on 13 Jul 11:54
u+3y = 17 u+3y-3y = 17-3y u= 17-3y u+6y=32 17-3y+6y=32 17+3y=32 17+3y-17=32-17 3y=15 3y/3=15/3 y=5 u= 17-3y u= 17-3(5) u= 17-15=2