Solve for each system 5y+2x=78 and 2y + 7x = 56

Asked by AnneS2 on 30 Jul 08:11

Last updated by anonymous on 01 Aug 17:33

Answered by CherieS on 01 Aug 17:33

5y+2x=78

5y-5y+2x=78-5y

2x=78-5y

2x/2=78-5y/2

x=39-2.5y

2y + 7x = 56

2y + 7(39-2.5y) = 56

2y + 7(39) (7)(-2.5y) = 56

2y+273-17.5y=56

273-15.5y=56

273-15.5y-273=56-273

-15.5y=-217

-15.5y/-15.5=-217/-15.5

y=14

x=39-2.5y

x=39-2.5*14

x=39-35=4