Math

Solve for each system 2x+2z=28 and 7x + 4z = 77

Asked by AnneS2 on 30 Jul 08:10

Last updated by anonymous on 01 Aug 17:41

1 Answers

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Answered by CherieS on 01 Aug 17:41

2x+2z=28

2x-2x+2z=28-2x

2z=28-2x

2z/2=28-2x/2

z=14-x

7x + 4z = 77

7x + 4(14-x) = 77

7x + 4(14) (4)(-x) = 77

7x+56-4x=77

3x+56=77

3x+56-56=77-56

3x=21

3x/3=21/3

x=7