Solve for each of the systems 8y+10z=178 and 4y + 2z = 62

4y + 2z = 62

4y-4y + 2z = 62-4y

2z = 62-4y

2z/2 = 62-4y/2

z=31-2y

8y+10z=178

8y+10(31-2y)=178

8y+10(31) (10)(-2y)=178

8y+310-20y=178

310-12y=178

310-12y-310=178-310

-12y=-132

-12y/-12=-132/-12

y=11

z=31-2y

z=31-2(11)

z=31-22=9