Math Solve for both systems: z+2x=29 and 3z + 2x = 43 Asked by AnneS2 on 13 Oct 06:30 Last updated by anonymous on 14 Oct 11:32
z+2x=29 z+2x-2x=29-2x z=29-2x 3z + 2x = 43 3(29-2x) + 2x = 43 3(29) (3)(-2x) + 2x = 43 87-6x+ 2x = 43 87-4x= 43 87-4x-87= 43-87 -4x=-44 -4x/-4=-44/-4 x=11 z=29-2x z=29-2(11) z=29-22=7