Math Solve for both systems z+2x=23 and 2z + 3x = 44 Asked by AnneS2 on 20 Jul 05:43 Last updated by anonymous on 21 Jul 11:31
z+2x=23 z+2x-2x=23-2x z=23-2x 2z + 3x = 44 2(23-2x) + 3x = 44 2(23) (2)(-2x) + 3x = 44 46-4x+3x=44 46-x=44 46-x-46=44-46 -x=-2 -x/-1=-2/-1 x=2 z=23-2x z=23-2(2) z=23-4=19