Math Solve for both systems z + y = 12 and 11z+6y=132 Asked by AnneS2 on 20 Aug 12:29 Last updated by anonymous on 21 Aug 17:46
z + y = 12 z-z + y = 12-z y = 12-z 11z+6y=132 11z+6(12-z)=132 11z+6(12) (6)(-z)=132 11z+72-6z=132 5z+72=132 5z+72-72=132-72 5z=60 5z/5=60/5 z=12 y = 12-z y = 12-12=0