Math
Solve for both systems y+7z=52 and 2y + z = 16
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Asked by
AnneS2
Last updated by
anonymous
y+7z=52
y+7z-7z=52-7z
y=52-7z
2y + z = 16
2(52-7z) + z = 16
2(52) (2)(-7z) + z = 16
104-14z+ z = 16
104-13z = 16
104-13z-104 = 16-104
-13z=-88
-13z/-13=-88/-13
z=6.77
y=52-7z
y=52-7(6.77)
y=52-47.38=4.62