Solve for both systems: y+7z=22 and 8y + 7z = 127

y+7z=22

y+7z-7z=22-7z

y=22-7z

8y + 7z = 127

8(22-7z) + 7z = 127

8(22) (8)(-7z) + 7z = 127

176-56z + 7z = 127

176-49z= 127

176-49z-176= 127-176

-49z=-49

-49z/-49=-49/-49

z=1

y=22-7z

y=22-7(1)

y=22-7=15