Math
Solve for both systems: y+3z=40 and 7y- 3z = 16
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Asked by
AnneS2
Last updated by
anonymous
y+3z=40
y+3z-3z=40-3z
y=40-3z
7y- 3z = 16
7(40-3z)- 3z = 16
7(40) (7)(-3z)- 3z = 16
280 -21z- 3z = 16
280 -24z= 16
280 -24z-280= 16-280
-24z=-264
-24z/-24=-264/-24
z=11
y=40-3z
y=40-3(11)
y=40-33=7