Math
Solve for both systems x - 5y = 40 and 3x + y = - 40
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Asked by
AnneS2
Last updated by
anonymous
x - 5y = 40
x - 5y+5y = 40+5y
x= 40+5y
3x + y = - 40
3(40+5y) + y = - 40
3(40) (3)(+5y) + y = - 40
120+15y+y=-40
120+16y=-40
120+16y-120=-40-120
16y=-160
16y/16=-160/16
y=-10
x= 40+5y
x= 40+5(-10)
x= 40-50=-10