Solve for both systems 8z+10y=192 and 3z - 10y = -93

Asked by AnneS2 on 04 Oct 06:46

Last updated by anonymous on 05 Oct 11:23

Answered by CherieS on 05 Oct 11:23

8z+10y=192

8z+10y-10y=192 -10y

8z=192 -10y

8z/8=192 -10y/8

z=24-1.25y

3z - 10y = -93

3(24-1.25y) - 10y = -93

3(24) (3)(-1.25y) - 10y = -93

72 -3.75y - 10y = -93

72 -13.75y= -93

72 -13.75y-72= -93-72

-13.75y= -165

-13.75y/-13.75= -165/-13.75

y=12

z=24-1.25y

z=24-1.25(12)

z=24-15=9