Math

Solve for both systems 6z+x=53 and 10z + 3x = 95

Asked by AnneS2 on 20 Jul 05:43

Last updated by anonymous on 21 Jul 11:35

1 Answers

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Answered by CherieS on 21 Jul 11:35

6z+x=53

6z-6z+x=53-6z

x=53-6z

10z + 3x = 95

10z + 3(53-6z) = 95

10z + 3(53) (3)(-6z) = 95

10z+159-18z=95

159-8z=95

159-159-8z=95-159

-8z=-64

-8z/-8=-64/-8

z=8

x=53-6z

x=53-6(8)

x=53-48=5