Math

Solve for both systems: 5z+y=46 and 3y + 6z = 57

Asked by
Last updated by anonymous
1 Answers
Log in to answer
5z+y=46 5z-5z+y=46-5z y=46-5z 3y + 6z = 57 3(46-5z) + 6z = 57 3(46) (3)(-5z) + 6z = 57 138-15z+ 6z = 57 138-9z = 57 138-9z-138 = 57-138 -9z=-81 -9z/-9=-81/-9 z=9 y=46-5z y=46-5(9) y=46-45=1