Math Solve for both systems 5x+7z=14 and 12x+2z=4 Asked by AnneS2 on 20 Aug 12:30 Last updated by anonymous on 21 Aug 17:37
12x+2z=4 12x-12x+2z=4-12x 2z=4-12x 2z/2=4-12x/2 z=2-6x 5x+7z=14 5x+7(2-6x)=14 5x+7(2) (7)(-6x)=14 5x+14-42x=14 14-37x=14 14-37x-14=14-14 -37x=0 -37x/-37=0/-37 x=0 z=2-6x z=2-6(0) z=2-2=2