Math
Solve for both systems 3z+10y=0 and 6z + 4y = 0
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Asked by
AnneS2
Last updated by
anonymous
3z+10y=0
3z+10y-10y=0-10y
3z=-10y
3z/3=-10y/3
z=-3.33y
6z + 4y = 0
6(-3.33y) + 4y = 0
-20y + 4y = 0
-16y = 0
-16y/-16 = 0/-16
y=0
z=-3.33y
z=-3.33(0)=0