Math Solve for both systems 3z+10y=0 and 6z + 4y = 0 Asked by AnneS2 on 28 Jul 09:00 Last updated by anonymous on 29 Jul 19:54
3z+10y=0 3z+10y-10y=0-10y 3z=-10y 3z/3=-10y/3 z=-3.33y 6z + 4y = 0 6(-3.33y) + 4y = 0 -20y + 4y = 0 -16y = 0 -16y/-16 = 0/-16 y=0 z=-3.33y z=-3.33(0)=0