Math

Solve for both systems 3y+z=1 and 12y + 5z = 5

Asked by AnneS2 on 22 Jul 05:12

Last updated by anonymous on 23 Jul 17:41

1 Answers

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Answered by CherieS on 23 Jul 17:41

3y+z=1

3y-3y+z=1-3y

z=1-3y

12y + 5z = 5

12y + 5(1-3y) = 5

12y + 5(1) (5)(-3y) = 5

12y+5-15y=5

5-3y=5

5-5-3y=5-5

-3y=0

-3y/-3=0/-3

y=0

z=1-3y

z=1-3(0)

z=1-0=1