Solve for both systems: 3x+5z=51 and 8x + z = 99

Asked by AnneS2 on 18 Oct 07:00

Last updated by anonymous on 19 Oct 12:24

Answered by CherieS on 19 Oct 12:24

3x+5z=51

3x+5z-5z=51-5z

3x=51-5z

3x/3=51-5z /3

x=17-1.67z

8x + z = 99

8(17-1.67z) + z = 99

8(17) (8)(-1.67z) + z = 99

136-13.36z + z = 99

136-12.36z= 99

136-12.36z-136= 99-136

-12.36z=-37

-12.36z/-12.36=-37/-12.36

z=3

x=17-1.67z

x=17-1.67(3)

x=17-5=2