Math Solve for both systems: 2x+7z=116 and 2x + 3z = 52 Asked by AnneS2 on 08 Oct 04:49 Last updated by anonymous on 09 Oct 11:46
2x+7z=116 2x+7z-7z=116-7z 2x=116-7z 2x/2=116-7z/2 x=58-3.5z 2x + 3z = 52 2(58-3.5z) + 3z = 52 2(58) (2)(-3.5z) + 3z = 52 116-7z + 3z = 52 116-4z = 52 116-4z-116 = 52-116 -4z=-64 -4z/-4=-64/-4 z=16 x=58-3.5z x=58-3.5(16) x=58-56=2