Math

Solve for both systems: 2x+2z=34 and 10x + 7z = 122

Asked by AnneS2 on 16 Sep 06:19

Last updated by anonymous on 17 Sep 21:46

1 Answers

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Answered by CherieS on 17 Sep 21:46

2x+2z=34

2x-2x+2z=34-2x

2z=34-2x

2z/2=34-2x/2

z=17-x

10x + 7z = 122

10x + 7(17-x) = 122

10x + 7(17) (7)(-x) = 122

10x+119-7x=122

119+3x=122

119+3x-119=122-119

3x=3

3x/3=3/3

x=1

z=17-x

z=17-1=16