Math

Solve for both systems 2x-z=2 and 3x + 9z = 66

Asked by AnneS2 on 12 Sep 03:18

Last updated by anonymous on 14 Sep 01:05

1 Answers

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Answered by CherieS on 14 Sep 01:05

2x-z=2

2x-z+z=2+z

2x=2+z

2x-2=2+z-2

2x-2=z

3x + 9z = 66

3x + 9(2x-2) = 66

3x + 9(2x) (9)(-2) = 66

3x+18x-18=66

21x-18=66

21x-18+18=66+18

21x=84

21x/21=84/21

x=4

2x-2=z

2(4)-2=z

8-2=z

6=z