Solve for both systems 2x + 3y = - 5 and 3x + 3y = - 3

3x + 3y = - 3

3x-3x + 3y = - 3-3x

3y = - 3-3x

3y/3 = - 3-3x/3

y=-1-x

2x + 3y = - 5

2x + 3(-1-x) = - 5

2x + 3(-1) (3)(-x) = - 5

2x-3-3x=-5

-3-x=-5

-3-x+3=-5+3

-x=-2

-x/-1=-2 /-1

x=2

y=-1-x

y=-1-2=-3