Math Solve for both systems 10z+9y=183 and 9z + 3y = 129 Asked by AnneS2 on 30 Jul 08:19 Last updated by anonymous on 31 Jul 17:46
9z + 3y = 129 9z-9z + 3y = 129-9z 3y = 129-9z 3y/3 = 129-9z/3 y=43-3z 10z+9y=183 10z+9(43-3z)=183 10z+9(43) (9)(-3z)=183 10z+387-27z=183 387-17z=183 387-17z-387=183-387 -17z=-204 -17z/-17=-204/-17 z=12 y=43-3z y=43-3(12) y=43-36=7