Solve for 3x + 2y = 5 and x + 5y = 32

x + 5y = 32

x + 5y-5y = 32-5y

x= 32-5y

3x + 2y = 5

3(32-5y) + 2y = 5

3(32) (3)(-5y) + 2y = 5

96-15y+2y=5

96-13y=5

96-13y-96=5-96

-13y=-91

-13y/-13=-91/-13

y=7

x= 32-5y

x= 32-5(7)

x=32-35

x=-3