Math Solve for 3u+z=15 and u+2z = 10 Asked by AnneS2 on 12 Jul 04:47 Last updated by anonymous on 13 Jul 12:01
u+2z = 10 u+2z-2z = 10-2z u= 10-2z 3u+z=15 3(10-2z)+z=15 3(10) (3)(-2z)+z=15 30-6z+z=15 30-5z=15 30-5z-30=15-30 -5z=-15 -5z/-5=-15/-5 z=3 u= 10-2z u= 10-2(3) u= 10-6=4