Math Solve for 3c+4u=33 and 6c+3u=36 Asked by AnneS2 on 12 Jul 04:49 Last updated by anonymous on 13 Jul 11:47
6c+3u=36 6c+3u-6c=36-6c 3u=36-6c 3u/3=36-6c/3 u=12-2c 3c+4u=33 3c+4(12-2c)=33 3c+(4)(12) (4)(-2c)=33 3c+48-8c=33 48-5c=33 48-5c-48=33-48 -5c=-15 -5c/-5=-15/-5 c=3 u=12-2c u=12-2(3) u=12-6=6