Math Solve and check x^2 - x - 42 = 0 Asked by AnneS2 on 04 Aug 08:02 Last updated by anonymous on 05 Aug 14:36
x^2 - x - 42 = 0 (x )(x ) ( -7)( +6)=0 (x-7) (x+6) = 0 Check: (x-7) (x+6) = 0 (x)(x) (x)(6) (-7)(x) (-7)(6) x^2 +6x -7x -42=0 x^2 -x -42=0 Solve: (x-7)=0 x-7+7=0+7 x=7 Solve: (x+6) = 0 x+6-6 = 0-6 x=-6