Math
Solve and check x^2 - x - 42 = 0

Asked by
AnneS2
Last updated by
anonymous
x^2 - x - 42 = 0
(x )(x ) ( -7)( +6)=0
(x-7) (x+6) = 0
Check:
(x-7) (x+6) = 0
(x)(x) (x)(6) (-7)(x) (-7)(6)
x^2 +6x -7x -42=0
x^2 -x -42=0
Solve:
(x-7)=0
x-7+7=0+7
x=7
Solve:
(x+6) = 0
x+6-6 = 0-6
x=-6