Math (n^2 -n-29) / (n-6)= Asked by AnneS2 12 years ago 8/5/2013 5:45 AM Last updated by anonymous 12 years ago 8/6/2013 11:37 AM
(n^2 -n-29) / (n-6)=n+5 r. 1 (n-6)(n+5) (n)(n) (n)(5) (-6)(n) (-6)(5) n^2 +5n -6n -30 n^2-n-30 n^2-n-29 -n^2+n+30 1
