Math (m^2- 7m-11) / (m-8)= Asked by AnneS2 12 years ago 8/5/2013 5:38 AM Last updated by anonymous 12 years ago 8/6/2013 1:02 PM
(m^2- 7m-11) / (m-8)=m+1 R.-3 (m-8)(m+1) (m)(m) (m)(1) (-8)(m) (-8)(1) m^2 +m -8m -8 m^2-7m-8=-(m^2-7m-8)=-m^2+7m+8 m^2- 7m-11 -m^2+7m+8 -3