Math Factor and solve: y^2 -4y+3=0 Asked by AnneS2 12 years ago 9/23/2013 5:40 AM Last updated by anonymous 12 years ago 9/25/2013 11:48 AM
y^2 -4y+3=0 (y )(y ) ( -3)( -1)=0 (y-3) (y-1) = 0 Solve: (y-3) =0 y-3+3 =0+3 y=3 Solve: (y-1) = 0 y-1+1 = 0+1 y=1
