Math Factor and solve 4y^2 +4y+1=0 Asked by AnneS2 on 20 Aug 12:26 Last updated by anonymous on 21 Aug 21:07
4y^2 +4y+1=0 (2y )(2y ) ( +1)( +1)=0 (2y+1)(2y+1)=0 (2 y+1)^2 = 0 Solve: (2y+1)=0 2y+1-1=0-1 2y=-1 2y/2=-1/2 y=-1/2
