Math Factor and solve 1x^2 + 14x + 48 = 0 Asked by AnneS2 on 26 Jul 06:41 Last updated by anonymous on 27 Jul 11:57
1x^2 + 14x + 48 = 0 (x )(x ) ( +6)( +8)=0 (x+6) (x+8) = 0 Solve: (x+6)=0 x+6-6=0-6 x=-6 Solve: (x+8) = 0 x+8-8 = 0-8 x=-8