Factor and solve 1x^2 + 14x + 48 = 0

Asked by AnneS2 12 years ago 7/26/2013 6:41 AM

Last updated by anonymous 12 years ago 7/27/2013 11:57 AM

Answered by CherieS 12 years ago 7/27/2013 11:57 AM

1x^2 + 14x + 48 = 0

(x )(x ) ( +6)( +8)=0

(x+6) (x+8) = 0

Solve:

(x+6)=0

x+6-6=0-6

x=-6

Solve:

(x+8) = 0

x+8-8 = 0-8

x=-8