Math
Factor and check x^2 - 21x + 108 = 0
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Asked by
AnneS2
Last updated by
anonymous
x^2 - 21x + 108 = 0
(x )(x ) ( -12)( -9)=0
(x-12) (x-9) = 0
Check:
(x-12) (x-9) = 0
(x)(X) (x)(-9) (-12)(x) (-12)(-9)=0
x^2 -9x -12x +108=0
x^2 -21x +108=0