Factor and check - 4x^2 + 8x - 4 = 0

Asked by AnneS2 on 14 Jun 09:46

Last updated by anonymous on 15 Jun 13:11

Answered by CherieS on 15 Jun 13:11

- 4x^2 + 8x - 4 = 0

-4(x^2-2x+1)=0

-4((x )(x ) ( -1)( -1))=0

-4((x-1)(x-1))=0

-4 (x-1)^2 = 0

Check

-4((x-1)(x-1))=0

-4((x)x) (x)(-1) (-1)(x) (-1)(-1))=0

-4(x^2-x-x+1)=0

-4(x^2-2x+1)=0

- 4x^2 + 8x - 4 = 0