Math b^2 +5b-35=3b Solve Asked by AnneS2 12 years ago 5/15/2013 5:27 AM Last updated by anonymous 5 years ago 9/22/2020 9:25 PM
b^2 +5b-35=3b b^2 +5b-35-3b=3b -3b b^2 +2b-35=0 (b )(b ) ( -5)( +7)=0 (b-5) (b+7) = 0 Solve: (b-5)=0 b-5+5=0+5 b=5 Solve: (b+7) = 0 b+7-7=0-7 b=-7