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> (b/-1)*b^2*4b
Math
(b/-1)*b^2*4b
Asked by
AnneS2
on 24 Mar 06:39
Last updated by
anonymous
on 25 Mar 23:29
1
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Answered by
CherieS
on 25 Mar 23:29
=(-b/1)*b^2 *4b
=-b*b^2=-b^1*b^2=-b^3 *4b
=-b^3*4b=-b^3*4b^1
=-4b^4