Math (a^2 -28) / (a-5)= Asked by AnneS2 12 years ago 8/5/2013 5:44 AM Last updated by anonymous 12 years ago 8/6/2013 11:48 AM
(a^2 -28) / (a-5)=a+5 r.-3 (a-5)(a+5) (a)(a) (a)(5) (-5)(a) (-5)(5) a^2 +5a -5a -25 a^2 0a -25 a^2-25=-(a^2-25)=-a+25 a^2-28 -a^2+25 -3