t(6t - 7) = 3

Holt McDougal Larson Algebra 1 Common Core Edition page ep9 number 48

Asked by Dee Dee on 30 Apr 10:06

Last updated by anonymous on 01 May 12:52

Answered by CherieS on 01 May 12:52

t(6t - 7) = 3

(t)(6t) (t)(-7)=3

6t^2-7t=3

6t^2-7t-3=3-3

6t^2-7t-3=0