Find the zeros of the polynomial function. f(x) = -x^2 + 24x + 180

Holt McDougal Larson Algebra 1 Common Core Edition page 528 number 38

Asked by Dee Dee on 25 Mar 10:24

Last updated by anonymous on 28 Mar 11:55

Answered by CherieS on 28 Mar 11:55

f(x) = -x^2 + 24x + 180

-1(x )(x ) ( -30)( +6)

-1(x-30)(x+6)

-1(x)(x) (x)(+6) (-30)(x) (-30)(+6)

-1 ( x2 +6x -30x -180 )

-1(x2-24x-180)

-x2+24x+180

Solve

-1(x-30)=0

-x+30=0

-x+30-30=0-30

-x=-30

-x/-1=-30/-1

x=30

Solve:

-1(x+6)=0

-x-6=0

-x-6+6=0+6

-x=6

-x/-1=6/-1

x=-6

zeros=30 and -6