56z^2 + 2 = 22z

Holt McDougal Larson Algebra 1 Common Core Edition page 539 number 36

Asked by Dee Dee on 25 Mar 10:42

Last updated by anonymous on 26 Mar 14:39

Answered by CherieS on 26 Mar 14:39

56z^2 + 2 = 22z

56^2+2-22z=22z-22z

56^2-22z+2=0

56^2 -22z +2 =0

2(28^2) -11z +1=0

2(4z )(7z ) ( -1)( -1)

Factor:

2(4z-1)(7z-1)

Check:

2 (+4z)(+7z) (+4z)(-1) (-1)(+7z) (-1)(-1)

2 +28z^2 -4z -7z +1

2(28^2-11z+1)

Simplify

2(4z-1)=0

Solve

2(4z-1)=0

(2)(4z) -(2)(1)=0

8z-2=0

8z-2+2=0+2

8z=2

8z/8=2/8

z=2/8=1/4

Simplify

2(7z-1)=0

Solve

2(7z-1)=0

(2)(7z) - (2)(1)=0

14z-2=0

14z-2+2=0+2

14z=2

14z/14=2/14

z=2/14=1/7