21z^2 + 85z - 26 = 0

Holt McDougal Larson Algebra 1 Common Core Edition page 563 number 24

Asked by Dee Dee on 26 Mar 10:10

Last updated by anonymous on 27 Mar 12:11

Answered by CherieS on 27 Mar 12:11

(3z )(7z ) ( +13)( -2)=0

(3z+13)(7z-2)=0

Check:

(3z)(7z) (3z)(-2) (+13)(7z) (+13)(-2)=0

21z^2 -6z +91z -26=0

21z^2 85z -26=0

21z^2+85z-26=0

Simplify

(3z+13)=0

Solve:

(3z+13)=0

3z+13-13=0-13

3z=-13

3z/3=-13/3

z=-13/3

Simplify:

(7z-2)=0

Solve:

(7z-2)=0

7z-2+2=0+2

7z=2

z=2/7