-16k^2 + 8k + 24 = 0

Holt McDougal Larson Algebra 1 Common Core Edition page 539 number 34

Asked by Dee Dee on 25 Mar 10:41

Last updated by anonymous on 26 Mar 14:04

Answered by CherieS on 26 Mar 14:04

All of divisible by 8

-8 (2k^2) +k +3=0

-8 (k )(2k ) +k ( +1)( -3)

-8(k+1)(2k-3)=0 Factored

Check Factor

-8 (k+1)(2k-3)=0

(k)(2k) +k(-3) +1(2k) +1(-3)

-8 ( 2k^2 -3k +2k -3)=0

-8(2k^2-1k-3)=0

-16k^2+8k+24=0

Simpify

-8(k+1)=0

Solve

-8(k+1)=0

-8/-8(k+1)=0/-8

k+1=0

k+1-1=0-1

k=-1

Simplify

-8(2k-3)=0

-8/-8(2k-3)=0/-8

2k-3=0

2k-3+3=0+3

2k=3

2k/2=3/2

k=3/2