Math

9x^2-66x+96=0

Asked by AnneS2 on 21 Apr 01:56

Last updated by anonymous on 22 Apr 22:24

1 Answers

Answered by CherieS on 22 Apr 22:24

9x^2-66x+96=0 3(3x^2-22x+32) 3 (x )(3x ) ( -2)( -16) 3(x-2)(3x-16) Solve: 3(x-2)=0 3(x) (3)(-2) 3x-6=0 3x-6+6=0+6 3x=6 3x/3=6/3 x=2 Solve: 3(3x-16)=0 3(3x) (3)(-16)=0 9x-48=0 9x-48+48=0+48 9x=48 9x/9=48/9 x=16/3