Math 9 * (4 / 4) + 9^2 / 3= Asked by AnneS2 12 years ago 8/18/2013 1:12 AM Last updated by anonymous 12 years ago 8/20/2013 6:47 AM
PEMDAS=(), exponents, *,/, +, - =9 * (4 / 4) + 9^2 / 3 =9 * (1) + 9^2 / 3 =9 * (1) + 81 / 3 =9 * (1) + 27 =9 + 27 =36