Math

8y^2 -38y+45=0

Asked by AnneS2 on 24 Apr 03:34

Last updated by anonymous on 26 Apr 22:50

1 Answers

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Answered by CherieS on 26 Apr 22:50

8y^2 -38y+45=0

(2y )(4y ) ( -5)( -9)

(2y-5)(4y-9)=0

Check:

(2y-5)(4y-9)

(2y)(4y) (2y)(-9) (-5)(4y) (-5)(-9)

8y^2 -18y -20y +45

8y^2 -38y +45